利用1H-核磁共振谱计算环化丁苯橡胶的环化度和溶剂参与量 |
Calculation of cyclization degree and incorporated solvent content of cyclized SBR by 1H-NMR |
|
DOI: |
中文关键词: 环化丁苯橡胶 1H-核磁共振 环化度 溶剂参与量 |
英文关键词: cyclized SBR 1H-NMR cyclization degree incorporated solvent content |
基金项目:国家自然科学基金资助项目(29574179) |
|
摘要点击次数: 953 |
全文下载次数: 728 |
中文摘要: |
对环化丁苯橡胶的1H-核磁共振谱进行了归属分析,并推导出计算环化度和溶剂参与量的公式。设环化丁苯橡胶的1H-核磁共振谱图中化学位移为7.0,5.4,4.9和3.0~0处的峰强度分别为A,B,C和D,则环化丁苯橡胶中丁二烯总物质的量X)=(B+C+D-2A)/7.1,未环化的丁二烯物质的量(Y)=B/2+C/4,参与反应的二甲苯物质的量(Z)=(17.5A-B-C-D)/46.5,环化度(P)=1-Y/X,溶剂参与量(W)=91.6Z/X 。 |
英文摘要: |
1H-NMR spectra of cyclized SBR was analysed and the equations to calculate the cyclization degree and the incorporated solvent content by 1H-NMR method were derived.The total butadiene content in cyclized SBR(x)=(B+C+D-2A)/7.1,the uncyclized butadiene content(Y)=B/2+C/4,the incorporated dimethyl benzene content(Z)=(17.5A-B-C-D)/46.5,the cyclization degree(P)=1-Y/X and the incorporated solvent content(W)=91.6Z/X,if the peak densities at the 7.0,5.4,4.9 and 3.0~0 chemical shifts in 1H-NMR spectra of cyclized SBR were A,B,C and D respectively. |
|
查看全文
查看/发表评论 下载PDF阅读器 |
关闭 |